# Sort array of objects by multiple properties with Swift Tuple

## Table of Contents

In my last article, How to sort by multiple properties in Swift, we learn how to sort an array of objects with multiple criteria.

The final implementation can sum up like this.

A multiple criteria sorting mean a sorting in which we compare the first criteria, and only if the first criteria is equals, we then go to the next one. We do this until we find a non-equals criterion.

Which can translate into pseoducode like this:

`let sortedObjects = objects.sorted { (lhs, rhs) in`

for (lhsCriteria, rhsCriteria) in [(lhsCrtria1, rhsCriteria1), (lhsCrtria2, rhsCriteria2), (lhsCrtria3, rhsCriteria3), ... , (lhsCrtriaN, rhsCriteriaN)] {

if lhsCriteria == rhsCriteria {

continue

}

return lhsCriteria < rhsCriteria

}

}

It involves declaring an array of predicates and looping, but we can remove most of that logic with **tuple**.

## Tuple comparison

Swift has overload comparison operators like <, >, <=, >= for us with the following implementation.

`/// Returns a Boolean value indicating whether the first tuple is ordered`

/// before the second in a lexicographical ordering.

///

/// Given two tuples `(a1, a2, ..., aN)` and `(b1, b2, ..., bN)`, the first

/// tuple is before the second tuple if and only if

/// `a1 < b1` or (`a1 == b1` and

/// `(a2, ..., aN) < (b2, ..., bN)`).

///

/// - Parameters:

/// - lhs: A tuple of `Comparable` elements.

/// - rhs: Another tuple of elements of the same type as `lhs`.

@inlinable public func < <A, B>(lhs: (A, B), rhs: (A, B)) -> Bool where A : Comparable, B : Comparable

I want you to focus on the following sentence:

`/// Given two tuples `(a1, a2, ..., aN)` and `(b1, b2, ..., bN)`, the first`

/// tuple is before the second tuple if and only if

/// `a1 < b1` or (`a1 == b1` and

/// `(a2, ..., aN) < (b2, ..., bN)`).

This is exactly how we implement our sorting. Let's compare that to our pseudocode. You can see that tuples comparison is how we compare our sorting criteria.

`let sortedObjects = objects.sorted { (lhs, rhs) in`

for (lhsCriteria, rhsCriteria) in [(lhsCrtria1, rhsCriteria1), (lhsCrtria2, rhsCriteria2), (lhsCrtria3, rhsCriteria3), ... , (lhsCrtriaN, rhsCriteriaN)] {

if lhsCriteria == rhsCriteria {

continue

}

return lhsCriteria < rhsCriteria

}

}

Let's implement the sorting using a tuple of criteria.

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## Example

We will use the same object as our last example.

`struct BlogPost {`

let title: String

let pageView: Int

let sessionDuration: Double

}

## Ascending order

To sort in ascending order, we use less than operator (`<`

) over tuples.

`let posts: [BlogPost] = [`

BlogPost(title: "Zoo", pageView: 5, sessionDuration: 1),

BlogPost(title: "Alice", pageView: 1, sessionDuration: 3),

BlogPost(title: "Alice", pageView: 1, sessionDuration: 2),

BlogPost(title: "Alice", pageView: 2, sessionDuration: 1),

BlogPost(title: "Zoo", pageView: 4, sessionDuration: 2),

BlogPost(title: "Abena", pageView: 4, sessionDuration: 10),

BlogPost(title: "Angero", pageView: 1, sessionDuration: 2)

]

let sorted = posts.sorted { (lhs, rhs) -> Bool in

return (lhs.title, lhs.pageView, lhs.sessionDuration) < (rhs.title, rhs.pageView, rhs.sessionDuration)

}

print(sorted)

Here is the result:

`[BlogPost(title: "Abena", pageView: 4, sessionDuration: 10.0),`

BlogPost(title: "Alice", pageView: 1, sessionDuration: 2.0),

BlogPost(title: "Alice", pageView: 1, sessionDuration: 3.0),

BlogPost(title: "Alice", pageView: 2, sessionDuration: 1.0),

BlogPost(title: "Angero", pageView: 1, sessionDuration: 2.0),

BlogPost(title: "Zoo", pageView: 4, sessionDuration: 2.0),

BlogPost(title: "Zoo", pageView: 5, sessionDuration: 1.0)]

This will compare the first element `lhs.title < rhs.title`

and if `lhs.title == rhs.title`

, we compare `(lhs.pageView, lhs.sessionDuration) < (rhs.pageView, rhs.sessionDuration)`

. This is identical to our previous implmentation.

## Descending order

To sort in descending order, we use less than operator (`<`

) over tuples.

`let posts: [BlogPost] = [`

BlogPost(title: "Zoo", pageView: 5, sessionDuration: 1),

BlogPost(title: "Alice", pageView: 1, sessionDuration: 3),

BlogPost(title: "Alice", pageView: 1, sessionDuration: 2),

BlogPost(title: "Alice", pageView: 2, sessionDuration: 1),

BlogPost(title: "Zoo", pageView: 4, sessionDuration: 2),

BlogPost(title: "Abena", pageView: 4, sessionDuration: 10),

BlogPost(title: "Angero", pageView: 1, sessionDuration: 2)

]

let sorted = posts.sorted { (lhs, rhs) -> Bool in

return (lhs.title, lhs.pageView, lhs.sessionDuration) > (rhs.title, rhs.pageView, rhs.sessionDuration)

}

print(sorted)

Here is the result:

`[BlogPost(title: "Zoo", pageView: 5, sessionDuration: 1.0),`

BlogPost(title: "Zoo", pageView: 4, sessionDuration: 2.0),

BlogPost(title: "Angero", pageView: 1, sessionDuration: 2.0),

BlogPost(title: "Alice", pageView: 2, sessionDuration: 1.0),

BlogPost(title: "Alice", pageView: 1, sessionDuration: 3.0),

BlogPost(title: "Alice", pageView: 1, sessionDuration: 2.0),

BlogPost(title: "Abena", pageView: 4, sessionDuration: 10.0)]

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## Different sort order on each element

If you want different sorting orders for each property, you can do that by **swap the element's position in the tuples.**

We can't change the operator for each element in the tuples, but swapping its position would result in the same effect. Consider the following examples.

`lhs.property1 < rhs.proerty1`

will sort in ascending order.

`lhs.property2 > rhs.proerty2`

will sort in descending order, but all elements must compare using the same operator. So, we swap the position.

`rhs.property2 < lhs.property2`

is equals to `lhs.property2 > rhs.property2`

which is descending sort.

So, if we want to sort `title`

in ascending order and sort `pageView`

and `sessionDuration`

in descending order, we can use the following code.

`let posts: [BlogPost] = [`

BlogPost(title: "Zoo", pageView: 5, sessionDuration: 1),

BlogPost(title: "Alice", pageView: 1, sessionDuration: 3),

BlogPost(title: "Alice", pageView: 1, sessionDuration: 2),

BlogPost(title: "Alice", pageView: 2, sessionDuration: 1),

BlogPost(title: "Zoo", pageView: 4, sessionDuration: 2),

BlogPost(title: "Abena", pageView: 4, sessionDuration: 10),

BlogPost(title: "Angero", pageView: 1, sessionDuration: 2)

]

let sorted = posts.sorted { (lhs, rhs) -> Bool in

return (lhs.title, rhs.pageView, rhs.sessionDuration) < (rhs.title, lhs.pageView, lhs.sessionDuration)

}

print(sorted)

## Caveats

We can only compare up to six properties using tuples. Swift only overload tuple comparison up to six elements.

`/// Returns a Boolean value indicating whether the first tuple is ordered`

/// after or the same as the second in a lexicographical ordering.

///

/// Given two tuples `(a1, a2, ..., aN)` and `(b1, b2, ..., bN)`, the first

/// tuple is after or the same as the second tuple if and only if

/// `a1 > b1` or (`a1 == b1` and

/// `(a2, ..., aN) >= (b2, ..., bN)`).

///

/// - Parameters:

/// - lhs: A tuple of `Comparable` elements.

/// - rhs: Another tuple of elements of the same type as `lhs`.

@inlinable public func >= <A, B, C, D, E, F>(lhs: (A, B, C, D, E, F), rhs: (A, B, C, D, E, F)) -> Bool where A : Comparable, B : Comparable, C : Comparable, D : Comparable, E : Comparable, F : Comparable

I would say six properties should be enough for most cases, but if it isn't, you can go back to my last implementation.

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